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CPUShack
Joined: 16 Jun 2003
Posts: 34259
Location: State of Jefferson, USA
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 Posted: Tue Nov 10, 2020 3:05 pm Post subject: CPU Shack: MIL C80008 Intel 1103 RAMs |
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Here are some nice Microsystems International Ltd (MIL) 1103 DRAMs
They are custom marked (or protos) but the die is clearly an 1103.
Very nice chips
22x MIL C80008 1103 DRAM $8 each or a pair for $13
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debs3759
Joined: 18 Jan 2006
Posts: 9477
Location: Northampton, Divided Kingdom
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| Posted: Tue Nov 10, 2020 3:09 pm Post subject: |
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A pair please
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brutuscat2
Joined: 03 Dec 2019
Posts: 212
Location: US
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| Posted: Tue Nov 10, 2020 3:22 pm Post subject: |
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| 2 for me, thanks. |
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stamasd
Joined: 05 Jun 2014
Posts: 1311
Location: Connecticut
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| Posted: Tue Nov 10, 2020 3:58 pm Post subject: |
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For fun here's a calculation on how many of those you would need to boot a very basic and stripped down modern OS. Assuming that if you're lucky enough you can boot a minimal Linux system based on a not too old kernel, stripped to the bare minimum, in 4MiB of RAM though that may be stretching it a lot.
one chip=1kx1bit; assuming these weigh about 5g each.
1kiB = 8 chips = 40g.
1MiB = 8 chips*1024 = 40g*1024 = 40.96kg
4MiB = 163.84kg
Under a more reasonable assumption of 16MiB, you're close to 1 ton.  |
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debs3759
Joined: 18 Jan 2006
Posts: 9477
Location: Northampton, Divided Kingdom
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| Posted: Tue Nov 10, 2020 4:08 pm Post subject: |
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LOL, you would need 4 just to load a simple boot sector And that's without the BIOS code.
I just like old memory
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My graphics card database can be found at http://www.gpuzoo.com.
I can resist anything except temptation.
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CPUShack
Joined: 16 Jun 2003
Posts: 34259
Location: State of Jefferson, USA
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| Posted: Tue Nov 10, 2020 4:12 pm Post subject: |
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| stamasd wrote: | For fun here's a calculation on how many of those you would need to boot a very basic and stripped down modern OS. Assuming that if you're lucky enough you can boot a minimal Linux system based on a not too old kernel, stripped to the bare minimum, in 4MiB of RAM though that may be stretching it a lot.
one chip=1kx1bit; assuming these weigh about 5g each.
1kiB = 8 chips = 40g.
1MiB = 8 chips*1024 = 40g*1024 = 40.96kg
4MiB = 163.84kg
Under a more reasonable assumption of 16MiB, you're close to 1 ton. |
Phew, thankfully these only weigh 2.5grams each, think of the savings!
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stevejam
Joined: 30 Dec 2017
Posts: 803
Location: Metaluna aka Bellevue WA
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| Posted: Tue Nov 10, 2020 4:15 pm Post subject: |
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| Pair please! |
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xsecret
Joined: 01 Feb 2004
Posts: 1847
Location: France
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stamasd
Joined: 05 Jun 2014
Posts: 1311
Location: Connecticut
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| Posted: Tue Nov 10, 2020 5:39 pm Post subject: |
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| debs3759 wrote: | LOL, you would need 4 just to load a simple boot sector And that's without the BIOS code.
I just like old memory |
Actually you would still need 8 to make it byte-wide. Unless you do some clever addressing gymnastics. |
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cvandijk
Joined: 21 Jul 2016
Posts: 3589
Location: Netherlands
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| Posted: Tue Nov 10, 2020 5:41 pm Post subject: |
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| A pair for me, thanks |
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Twinrocket
Joined: 04 Apr 2012
Posts: 558
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| Posted: Tue Nov 10, 2020 6:52 pm Post subject: |
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| A pair for me, thanks |
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Bator
Joined: 28 Oct 2013
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Location: Russia / Yakutia & Siberia
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xhoba
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tunder10
Joined: 08 Nov 2006
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Location: italy
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| Posted: Wed Nov 11, 2020 2:45 am Post subject: |
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| one for me, thanks |
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CPUShack
Joined: 16 Jun 2003
Posts: 34259
Location: State of Jefferson, USA
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